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Old 10-19-2007   #1 (permalink)
navya
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Default A Ferrari moving at 100 km/h is 80 km behind a Jaguar moving in the same direction...

...at 60 km/h.? How far does the Ferrari travel before it catches up with the Jaguar?
urgent?????????????
 
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Old 10-19-2007   #2 (permalink)
eclipse
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F-------------------J----------------------Z-

F is position of Farrari
J is position of Jaguar
Distance FJ is 80 km
Z is the position where Farrari catches up with Jaguar.
Let FZ distance be "x"

Now,
the time "t" taken by the vehicles to reach at point "Z" is equal

Hence

t for farrari = t for jaguar
FZ/(speed of farrari) = JZ/(speed of jaguar)
x/100 = (x-80)/60
x/10 = (x-80)/6
6x = 10x - 800
4x = 800
x = 200 km

So, the distace at which farrati catches up with jaguar is 200 kms.
 
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