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#2 (permalink) |
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F-------------------J----------------------Z-
F is position of Farrari J is position of Jaguar Distance FJ is 80 km Z is the position where Farrari catches up with Jaguar. Let FZ distance be "x" Now, the time "t" taken by the vehicles to reach at point "Z" is equal Hence t for farrari = t for jaguar FZ/(speed of farrari) = JZ/(speed of jaguar) x/100 = (x-80)/60 x/10 = (x-80)/6 6x = 10x - 800 4x = 800 x = 200 km So, the distace at which farrati catches up with jaguar is 200 kms. |
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